generate/constraint_comprehension/solver.py: solve_two_var_linear (order-independent 2x2 integer Cramer's rule over typed constraints), the solve_two_var_count_weight specialization, and solve/answer_constraint_problem driving it from a ConstraintProblem. Four typed refusals: indistinguishable_weights (det==0), non_integer_solution (numer%det!=0, never rounds), negative_solution, verification_failed (identity backstop). Ties to the C2 gold: solves all 7 solved fixtures to their gold value and refuses all 3 solver_refuses fixtures with EXACTLY the gold-claimed reason (the gold's reason is now solver-verified, not just annotation). Per-refusal meaningful-fail + positive re-substitution. Off-serving. 9 tests.
106 lines
5.2 KiB
Python
106 lines
5.2 KiB
Python
"""Independent exact integer solver for the R2 two-variable linear system.
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Solves a two-variable, two-equation integer linear system by **exact Cramer's rule** — no
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floats, no nearest-option snapping. The R2 analogue of the relational-metric answer oracle:
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an independent decision procedure that consumes the *structured* constraints, never the text.
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Refusal-first (the wrong=0 boundary). The four ways a count/weight system has no honest
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nonnegative-integer answer each REFUSE with a typed reason, never a guessed value:
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- ``indistinguishable_weights`` — the system is singular (``det == 0``): the two equations
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cannot separate the unknowns (e.g. equal per-category coefficients), so no unique solution.
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- ``non_integer_solution`` — Cramer's numerator is not divisible by the determinant:
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no integer solution exists; the solver refuses rather than round.
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- ``negative_solution`` — a solved value is negative: invalid in the count domain.
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- ``verification_failed`` — a defensive re-substitution backstop (an algebraic identity
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for the closed-form Cramer solution, so unreachable while the derivation is correct; retained
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as a structural guard against future edits, NOT claimed as an independently-triggerable gate).
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The convenience ``solve_two_var_count_weight`` is the canonical ``x + y = N`` /
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``a·x + b·y = T`` specialization; ``solve_constraint_problem`` / ``answer_constraint_problem``
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drive it from a typed :class:`ConstraintProblem`. Off-serving: imports no
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``generate.derivation`` / ``core.reliability_gate``. Deterministic; no clock, no randomness.
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"""
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from __future__ import annotations
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from generate.constraint_comprehension.expr import LinearConstraint, LinearExpr
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from generate.constraint_comprehension.model import ConstraintProblem
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from generate.meaning_graph.reader import Refusal
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def _coeffs(constraint: LinearConstraint, x: str, y: str) -> tuple[int, int, int]:
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"""``(coeff_x, coeff_y, rhs - lhs_constant)`` for ``constraint`` over the variables x, y."""
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cx = cy = 0
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for symbol, coeff in constraint.lhs.terms:
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if symbol == x:
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cx += coeff
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elif symbol == y:
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cy += coeff
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return cx, cy, constraint.rhs - constraint.lhs.constant
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def solve_two_var_linear(
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c0: LinearConstraint, c1: LinearConstraint, *, nonnegative: bool = True
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) -> dict[str, int] | Refusal:
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"""Solve a 2-variable, 2-equation integer system over the SAME two symbols by Cramer's rule.
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Precondition (guaranteed upstream by the C2 setup validator / the reader): both constraints
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are ``eq`` over exactly two shared symbols. Returns ``{symbol: value}`` or a typed
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:class:`Refusal` carrying one of the four solver reasons.
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"""
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symbols = sorted({s for c in (c0, c1) for s, _ in c.lhs.terms})
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if len(symbols) != 2: # contract violation — upstream must guarantee two variables
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raise ValueError(f"solver expects exactly two variables; got {symbols}")
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x, y = symbols
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p, q, r0 = _coeffs(c0, x, y)
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r, s, r1 = _coeffs(c1, x, y)
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det = p * s - q * r
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if det == 0:
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return Refusal("indistinguishable_weights", f"singular system over {x}/{y}")
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num_x = r0 * s - q * r1
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num_y = p * r1 - r0 * r
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if num_x % det != 0 or num_y % det != 0:
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return Refusal("non_integer_solution", f"no integer solution for {x}/{y}")
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vx, vy = num_x // det, num_y // det
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if nonnegative and (vx < 0 or vy < 0):
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return Refusal("negative_solution", f"{x}={vx}, {y}={vy}")
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if p * vx + q * vy != r0 or r * vx + s * vy != r1: # pragma: no cover - identity backstop
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return Refusal("verification_failed", "solution failed re-substitution")
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return {x: vx, y: vy}
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def solve_two_var_count_weight(
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x: str, y: str, total_count: int, x_weight: int, y_weight: int, weighted_total: int
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) -> dict[str, int] | Refusal:
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"""The canonical specialization: ``x + y = total_count`` and
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``x_weight·x + y_weight·y = weighted_total``. ``x`` / ``y`` are the symbol names."""
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count = LinearConstraint(LinearExpr(((x, 1), (y, 1))), "eq", total_count)
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weighted = LinearConstraint(LinearExpr(((x, x_weight), (y, y_weight))), "eq", weighted_total)
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return solve_two_var_linear(count, weighted)
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def solve_constraint_problem(problem: ConstraintProblem) -> dict[str, int] | Refusal:
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"""Solve a two-constraint :class:`ConstraintProblem`'s system (order-independent)."""
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if len(problem.constraints) != 2: # contract violation — upstream guarantees two
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raise ValueError(f"solver expects exactly two constraints; got {len(problem.constraints)}")
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return solve_two_var_linear(problem.constraints[0], problem.constraints[1])
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def answer_constraint_problem(problem: ConstraintProblem) -> int | Refusal:
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"""Solve, then project to the asked unknown's value (or propagate the refusal)."""
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solution = solve_constraint_problem(problem)
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if isinstance(solution, Refusal):
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return solution
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if problem.query.symbol not in solution: # pragma: no cover - query is a category (C2)
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return Refusal("query_target_unsolved", problem.query.symbol)
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return solution[problem.query.symbol]
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__all__ = [
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"answer_constraint_problem",
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"solve_constraint_problem",
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"solve_two_var_count_weight",
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"solve_two_var_linear",
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]
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