""" Conformal Geometric Algebra geometry on Cl(4,1). Signature: (+,+,+,+,-), with Euclidean coordinates on e1,e2,e3. The two conformal null directions are built from e4 and e5: n_o = 0.5 * (e4 - e5) # origin, n_o^2 = 0 n_inf = e4 + e5 # infinity, n_inf^2 = 0 n_o · n_inf = -1 A Euclidean point x embeds as: X = x + n_o + 0.5 * |x|^2 * n_inf Then X·X = 0 and X·Y = -0.5 * ||x-y||^2. This is the ONLY distance metric in CORE-AI. No cosine similarity. No L2 norm. No approximate indexing. """ import numpy as np from .cl41 import geometric_product, scalar_part, basis_vector, N_COMPONENTS # Basis-vector component indices for e4/e5 inside the grade-1 block. # component 1=e1, 2=e2, 3=e3, 4=e4, 5=e5. _E4_IDX = 4 _E5_IDX = 5 def cga_inner(X: np.ndarray, Y: np.ndarray) -> float: """ Symmetric inner product: 0.5 * scalar_part(X*Y + Y*X). For null vectors representing conformal points: equals -d^2 / 2. """ XY = geometric_product(X, Y) YX = geometric_product(Y, X) return 0.5 * scalar_part(XY + YX) def outer_product(X: np.ndarray, Y: np.ndarray) -> np.ndarray: """ Outer (wedge) product: X ^ Y. For a prompt versor X_p and response versor X_r, X_p ^ X_r is a grade-2 object encoding their geometric relationship. """ XY = geometric_product(X, Y) YX = geometric_product(Y, X) return 0.5 * (XY - YX) def is_null(X: np.ndarray, tol: float = 1e-6) -> bool: """Check if X lies on the null cone: X·X = 0.""" return abs(cga_inner(X, X)) < tol def null_project(X: np.ndarray) -> np.ndarray: """ Re-project X onto the null cone by extracting its Euclidean part and re-embedding it with the canonical CGA point map. """ euclidean = np.asarray(X, dtype=np.float32)[1:4].copy() return embed_point(euclidean) def embed_point(x: np.ndarray) -> np.ndarray: """ Embed a Euclidean point x in R^3 into the CGA null cone. X = x + n_o + 0.5|x|^2 n_inf, where n_o = 0.5(e5-e4), n_inf = e4+e5. """ x = np.asarray(x, dtype=np.float32) assert len(x) == 3, "embed_point expects a 3D vector" x_sq = float(np.dot(x, x)) result = np.zeros(N_COMPONENTS, dtype=np.float32) result[1:4] = x # n_o + 0.5|x|^2 n_inf # e4 coefficient: -0.5 + 0.5|x|^2 # e5 coefficient: 0.5 + 0.5|x|^2 result[_E4_IDX] = 0.5 * (x_sq - 1.0) result[_E5_IDX] = 0.5 * (x_sq + 1.0) return result